`跪求``寻解不等式```谢谢``谢谢``!!!
来源:百度知道 编辑:UC知道 时间:2024/05/21 20:25:12
解不等式``谢谢``
(1) 2(5X+3)≤X-3(1-2X)
(2)X-1/2 - X+4/3 >-2
(3)-1<2X+3/7<5
解不等式组,并写出不等式组的正整数解``谢谢``
{不等式组} X-1/2≤1
X-2<4(X+1)
(1) 2(5X+3)≤X-3(1-2X)
(2)X-1/2 - X+4/3 >-2
(3)-1<2X+3/7<5
解不等式组,并写出不等式组的正整数解``谢谢``
{不等式组} X-1/2≤1
X-2<4(X+1)
(1) 2(5X+3)≤X-3(1-2X)
10X+6≤X-3+6X=7X-3
3X≤-9
X>=-3
(2)X-1/2 - X+4/3 >-2
请你把括号补全,谢谢!
(3)-1<2X+3/7<5
-7<14X+3<35
-10<14X<32
-5/7<X<16/7
X-1/2≤1 --->2X-1≤2--->X<3/2
X-2<4(X+1)---->X-2<4X+4--->-6<3X---->X>-2
So -2<X<3/2
X=-1,0,1
(1) 2(5X+3)≤X-3(1-2X)
10x+6<=x-3+6x
3x<=-9
x<=-3
(2)X-1/2 - X+4/3 >-2
3x-3-2x-8>-12
x>-1
(3)-1<2X+3/7<5
-7<2x+3<35
-10<2x<70
-5<x<35
解不等式组,并写出不等式组的正整数解``谢谢``
X-1/2≤1 <1>
X-2<4(X+1) <2>
由<1>得
x<=3/2
由<2>得
x-2<4x+4
3x>-6
x>-2
则
-2<x<=3/2
x=-1.0.1